DATE:29-12-2017
sol:-
C-CODE:
#include<stdio.h>
void main(){
int n,i,j,k;
scanf("%d",&n);
for(i=0;i<n;i++){
for(j=0;j<i;j++){printf(" ");}
for(k=n;k>i;k--){
if((n-k+1)%2==0){
printf("1");}
else{printf("0");}
printf(" ");}
printf("\n");}}
Q)Pattern 4 (Id-3460)
Given the value of ‘n’, develop an algorithm and write a C program to print the following pattern. When the value of ‘n’ is 5, the pattern will look as follows:
0 1 0 1 0 1
0 1 0 1 0
0 1 0 1
0 1 0
0 1
0
Input Format
First line contains the value of ‘n’
Output Format
Print the pattern given in the questionsol:-
C-CODE:
#include<stdio.h>
void main(){
int n,i,j,k;
scanf("%d",&n);
for(i=0;i<n;i++){
for(j=0;j<i;j++){printf(" ");}
for(k=n;k>i;k--){
if((n-k+1)%2==0){
printf("1");}
else{printf("0");}
printf(" ");}
printf("\n");}}
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